request.getSession().invalidate() method. Thus in a simple servlet following code will be the code for logout: public void doGet(HttpServletRequest request, HttpServletResponse response) throws
ServletException, IOException {
request.getSession().invalidate();
response.sendRedirect("/sampleapplication/index.jsp");
}
Code language: Java (java)<form method="post" action="ibm_security_logout" name="logoutForm">
<input type="hidden" name="logoutExitPage" VALUE="/sampleapplication/index.jsp" >
Click here to logout:
<input type="submit" name="logout" value="Logout">
</form>
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View Comments
I used the servlet code for LogOut utility. After logging our I am redirecting the browser to Log-in page. And on login page when user clicks on the back button, my application goes to the previous page from where user has executed logout.
Kindly help.
Thank you.